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The shift operations for dynamic_bitset fail to zero out words where the non-zero bits were shifted to a completely different word. For a right shift we don't need to sanitize the unused bits in the high word, because we know they were already clear and a right shift doesn't change that. libstdc++-v3/ChangeLog: PR libstdc++/115399 * include/tr2/dynamic_bitset (operator>>=): Remove redundant call to _M_do_sanitize. * include/tr2/dynamic_bitset.tcc (_M_do_left_shift): Zero out low bits in words that should no longer be populated. (_M_do_right_shift): Likewise for high bits. * testsuite/tr2/dynamic_bitset/pr115399.cc: New test. |
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