2022-06-01 13:55:33 +00:00
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export type Data = { [key: string]: unknown }
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export type UnionToIntersection<U> = (
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U extends any ? (k: U) => void : never
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) extends (k: infer I) => void
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? I
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: never
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// Conditional returns can enforce identical types.
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// See here: https://github.com/Microsoft/TypeScript/issues/27024#issuecomment-421529650
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// prettier-ignore
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type Equal<Left, Right> =
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(<U>() => U extends Left ? 1 : 0) extends (<U>() => U extends Right ? 1 : 0) ? true : false;
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export type HasDefined<T> = Equal<T, unknown> extends true ? false : true
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2022-07-05 02:12:21 +00:00
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2022-12-14 08:43:02 +00:00
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// If the type T accepts type "any", output type Y, otherwise output type N.
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2022-07-05 02:12:21 +00:00
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// https://stackoverflow.com/questions/49927523/disallow-call-with-any/49928360#49928360
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export type IfAny<T, Y, N> = 0 extends 1 & T ? Y : N
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export type LooseRequired<T> = { [P in string & keyof T]: T[P] }
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