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25b21e478e
The 'overlapped' value sets the UV_OVERLAPPED_PIPE libuv flag in the child process stdio. Fixes: https://github.com/nodejs/node/issues/29238 PR-URL: https://github.com/nodejs/node/pull/29412 Reviewed-By: Antoine du Hamel <duhamelantoine1995@gmail.com> Reviewed-By: James M Snell <jasnell@gmail.com>
52 lines
1.1 KiB
C
52 lines
1.1 KiB
C
#include <stdio.h>
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#include <string.h>
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#include <stdlib.h>
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#include <errno.h>
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#include <unistd.h>
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static size_t r(char* buf, size_t buf_size) {
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ssize_t read_count;
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do
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read_count = read(0, buf, buf_size);
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while (read_count < 0 && errno == EINTR);
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if (read_count <= 0)
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abort();
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return (size_t)read_count;
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}
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static void w(const char* buf, size_t count) {
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const char* end = buf + count;
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while (buf < end) {
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ssize_t write_count;
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do
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write_count = write(1, buf, count);
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while (write_count < 0 && errno == EINTR);
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if (write_count <= 0)
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abort();
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buf += write_count;
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}
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fprintf(stderr, "%zu", count);
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fflush(stderr);
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}
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int main(void) {
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w("0", 1);
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while (1) {
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char buf[256];
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size_t read_count = r(buf, sizeof(buf));
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// The JS part (test-child-process-stdio-overlapped.js) only writes the
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// "exit" string when the buffer is empty, so the read is guaranteed to be
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// atomic due to it being less than PIPE_BUF.
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if (!strncmp(buf, "exit", read_count)) {
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break;
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}
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w(buf, read_count);
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}
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return 0;
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}
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