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0b2497f16e
* fix: update codebase to work with Deno RC * work * fix * fix * fix * fixes * work * update * fixes * fix * revert
203 lines
6.3 KiB
TypeScript
203 lines
6.3 KiB
TypeScript
// Copyright 2018-2024 the Deno authors. All rights reserved. MIT license.
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// This module is browser compatible.
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import { assertEquals } from "./equals.ts";
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/**
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* Make an assertion that `expected` object is a subset of `actual` object,
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* deeply. If not, then throw.
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*
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* @example Usage
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* ```ts ignore
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* import { assertObjectMatch } from "@std/assert";
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*
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* assertObjectMatch({ foo: "bar" }, { foo: "bar" }); // Doesn't throw
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* assertObjectMatch({ foo: "bar" }, { foo: "baz" }); // Throws
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* assertObjectMatch({ foo: 1, bar: 2 }, { foo: 1 }); // Doesn't throw
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* assertObjectMatch({ foo: 1 }, { foo: 1, bar: 2 }); // Throws
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* ```
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*
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* @example Usage with nested objects
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* ```ts ignore
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* import { assertObjectMatch } from "@std/assert";
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*
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* assertObjectMatch({ foo: { bar: 3, baz: 4 } }, { foo: { bar: 3 } }); // Doesn't throw
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* assertObjectMatch({ foo: { bar: 3 } }, { foo: { bar: 3, baz: 4 } }); // Throws
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* ```
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*
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* @param actual The actual value to be matched.
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* @param expected The expected value to match.
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* @param msg The optional message to display if the assertion fails.
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*/
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export function assertObjectMatch(
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// deno-lint-ignore no-explicit-any
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actual: Record<PropertyKey, any>,
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expected: Record<PropertyKey, unknown>,
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msg?: string,
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): void {
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return assertEquals(
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// get the intersection of "actual" and "expected"
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// side effect: all the instances' constructor field is "Object" now.
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filter(actual, expected),
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// set (nested) instances' constructor field to be "Object" without changing expected value.
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// see https://github.com/denoland/deno_std/pull/1419
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filter(expected, expected),
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msg,
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);
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}
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type loose = Record<PropertyKey, unknown>;
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function isObject(val: unknown): boolean {
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return typeof val === "object" && val !== null;
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}
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function filter(a: loose, b: loose): loose {
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const seen = new WeakMap();
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return filterObject(a, b);
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function filterObject(a: loose, b: loose): loose {
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// Prevent infinite loop with circular references with same filter
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if ((seen.has(a)) && (seen.get(a) === b)) {
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return a;
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}
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try {
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seen.set(a, b);
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} catch (err) {
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if (err instanceof TypeError) {
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throw new TypeError(
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`Cannot assertObjectMatch ${a === null ? null : `type ${typeof a}`}`,
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);
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}
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}
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// Filter keys and symbols which are present in both actual and expected
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const filtered = {} as loose;
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const keysA = Reflect.ownKeys(a);
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const keysB = Reflect.ownKeys(b);
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const entries = keysA.filter((key) => keysB.includes(key))
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.map((key) => [key, a[key as string]]) as Array<[string, unknown]>;
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if (keysA.length && keysB.length && !entries.length) {
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// If both objects are not empty but don't have the same keys or symbols,
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// returns the entries in object a.
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for (const key of keysA) {
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filtered[key] = a[key];
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}
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return filtered;
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}
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for (const [key, value] of entries) {
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// On regexp references, keep value as it to avoid loosing pattern and flags
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if (value instanceof RegExp) {
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filtered[key] = value;
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continue;
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}
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const subset = (b as loose)[key];
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// On array references, build a filtered array and filter nested objects inside
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if (Array.isArray(value) && Array.isArray(subset)) {
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filtered[key] = filterArray(value, subset);
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continue;
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}
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// On nested objects references, build a filtered object recursively
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if (isObject(value) && isObject(subset)) {
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// When both operands are maps, build a filtered map with common keys and filter nested objects inside
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if ((value instanceof Map) && (subset instanceof Map)) {
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filtered[key] = new Map(
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[...value].filter(([k]) => subset.has(k)).map(
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([k, v]) => {
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const v2 = subset.get(k);
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if (isObject(v) && isObject(v2)) {
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return [k, filterObject(v as loose, v2 as loose)];
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}
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return [k, v];
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},
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),
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);
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continue;
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}
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// When both operands are set, build a filtered set with common values
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if ((value instanceof Set) && (subset instanceof Set)) {
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filtered[key] = value.intersection(subset);
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continue;
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}
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filtered[key] = filterObject(value as loose, subset as loose);
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continue;
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}
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filtered[key] = value;
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}
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return filtered;
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}
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function filterArray(a: unknown[], b: unknown[]): unknown[] {
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// Prevent infinite loop with circular references with same filter
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if (seen.has(a) && (seen.get(a) === b)) {
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return a;
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}
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seen.set(a, b);
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const filtered: unknown[] = [];
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const count = Math.min(a.length, b.length);
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for (let i = 0; i < count; ++i) {
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const value = a[i];
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const subset = b[i];
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// On regexp references, keep value as it to avoid loosing pattern and flags
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if (value instanceof RegExp) {
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filtered.push(value);
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continue;
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}
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// On array references, build a filtered array and filter nested objects inside
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if (Array.isArray(value) && Array.isArray(subset)) {
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filtered.push(filterArray(value, subset));
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continue;
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}
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// On nested objects references, build a filtered object recursively
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if (isObject(value) && isObject(subset)) {
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// When both operands are maps, build a filtered map with common keys and filter nested objects inside
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if ((value instanceof Map) && (subset instanceof Map)) {
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const map = new Map(
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[...value].filter(([k]) => subset.has(k))
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.map(([k, v]) => {
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const v2 = subset.get(k);
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if (isObject(v) && isObject(v2)) {
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return [k, filterObject(v as loose, v2 as loose)];
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}
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return [k, v];
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}),
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);
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filtered.push(map);
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continue;
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}
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// When both operands are set, build a filtered set with common values
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if ((value instanceof Set) && (subset instanceof Set)) {
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filtered.push(value.intersection(subset));
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continue;
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}
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filtered.push(filterObject(value as loose, subset as loose));
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continue;
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}
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filtered.push(value);
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}
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return filtered;
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}
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}
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